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55806471581317 is a prime number
BaseRepresentation
bin11001011000001011101001…
…11010100010111010000101
321022121001020221211112011121
430230011310322202322011
524303313123211100232
6314405050014433541
714516612250466312
oct1454056472427205
9238531227745147
1055806471581317
1116866434377156
1263138025028b1
13251a6b2444462
14dad0949ddd09
1566b9c38add97
hex32c174ea2e85

55806471581317 has 2 divisors, whose sum is σ = 55806471581318. Its totient is φ = 55806471581316.

The previous prime is 55806471581281. The next prime is 55806471581347. The reversal of 55806471581317 is 71318517460855.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 54331434612196 + 1475036969121 = 7370986^2 + 1214511^2 .

It is a cyclic number.

It is not a de Polignac number, because 55806471581317 - 235 = 55772111842949 is a prime.

It is a super-2 number, since 2×558064715813172 (a number of 28 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (55806471581347) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27903235790658 + 27903235790659.

It is an arithmetic number, because the mean of its divisors is an integer number (27903235790659).

Almost surely, 255806471581317 is an apocalyptic number.

It is an amenable number.

55806471581317 is a deficient number, since it is larger than the sum of its proper divisors (1).

55806471581317 is an equidigital number, since it uses as much as digits as its factorization.

55806471581317 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 28224000, while the sum is 61.

The spelling of 55806471581317 in words is "fifty-five trillion, eight hundred six billion, four hundred seventy-one million, five hundred eighty-one thousand, three hundred seventeen".