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55840117 is a prime number
BaseRepresentation
bin1101010100000…
…0110101110101
310220001222020111
43111000311311
5103243340432
65312503021
71245430114
oct325006565
9126058214
1055840117
112957a563
121684aa71
13b7516b8
1475b7c7b
154d80347
hex3540d75

55840117 has 2 divisors, whose sum is σ = 55840118. Its totient is φ = 55840116.

The previous prime is 55840097. The next prime is 55840133. The reversal of 55840117 is 71104855.

55840117 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 29224836 + 26615281 = 5406^2 + 5159^2 .

It is a cyclic number.

It is not a de Polignac number, because 55840117 - 219 = 55315829 is a prime.

It is a super-3 number, since 3×558401173 (a number of 24 digits) contains 333 as substring.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (55840157) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27920058 + 27920059.

It is an arithmetic number, because the mean of its divisors is an integer number (27920059).

Almost surely, 255840117 is an apocalyptic number.

It is an amenable number.

55840117 is a deficient number, since it is larger than the sum of its proper divisors (1).

55840117 is an equidigital number, since it uses as much as digits as its factorization.

55840117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5600, while the sum is 31.

The square root of 55840117 is about 7472.6245054867. The cubic root of 55840117 is about 382.2217880938.

The spelling of 55840117 in words is "fifty-five million, eight hundred forty thousand, one hundred seventeen".