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5601010050113 is a prime number
BaseRepresentation
bin101000110000001011000…
…1101101110010001000001
3201211110012000120001011212
41101200112031232101001
51213231332033100423
615525022443415505
71115442151616522
oct121402615562101
921743160501155
105601010050113
11186a414178715
1276561ab24595
1331823306a25a
14155139c32849
159aa660a8578
hex5181636e441

5601010050113 has 2 divisors, whose sum is σ = 5601010050114. Its totient is φ = 5601010050112.

The previous prime is 5601010050007. The next prime is 5601010050121. The reversal of 5601010050113 is 3110500101065.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 5353332630529 + 247677419584 = 2313727^2 + 497672^2 .

It is a cyclic number.

It is not a de Polignac number, because 5601010050113 - 218 = 5601009787969 is a prime.

It is not a weakly prime, because it can be changed into another prime (5601010050193) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2800505025056 + 2800505025057.

It is an arithmetic number, because the mean of its divisors is an integer number (2800505025057).

Almost surely, 25601010050113 is an apocalyptic number.

It is an amenable number.

5601010050113 is a deficient number, since it is larger than the sum of its proper divisors (1).

5601010050113 is an equidigital number, since it uses as much as digits as its factorization.

5601010050113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 450, while the sum is 23.

Adding to 5601010050113 its reverse (3110500101065), we get a palindrome (8711510151178).

The spelling of 5601010050113 in words is "five trillion, six hundred one billion, ten million, fifty thousand, one hundred thirteen".