Base | Representation |
---|---|
bin | 110100010000011110… |
… | …011110101110110101 |
3 | 12100211110202011100202 |
4 | 310100132132232311 |
5 | 1404403404004001 |
6 | 41435501250245 |
7 | 4024324430513 |
oct | 642036365665 |
9 | 170743664322 |
10 | 56111000501 |
11 | 21884219196 |
12 | aa5b563985 |
13 | 53a2b3135a |
14 | 2a041954b3 |
15 | 16d610696b |
hex | d1079ebb5 |
56111000501 has 2 divisors, whose sum is σ = 56111000502. Its totient is φ = 56111000500.
The previous prime is 56111000447. The next prime is 56111000503. The reversal of 56111000501 is 10500011165.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 33699413476 + 22411587025 = 183574^2 + 149705^2 .
It is a cyclic number.
It is not a de Polignac number, because 56111000501 - 214 = 56110984117 is a prime.
Together with 56111000503, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (56111000503) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28055500250 + 28055500251.
It is an arithmetic number, because the mean of its divisors is an integer number (28055500251).
Almost surely, 256111000501 is an apocalyptic number.
It is an amenable number.
56111000501 is a deficient number, since it is larger than the sum of its proper divisors (1).
56111000501 is an equidigital number, since it uses as much as digits as its factorization.
56111000501 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 150, while the sum is 20.
Adding to 56111000501 its reverse (10500011165), we get a palindrome (66611011666).
The spelling of 56111000501 in words is "fifty-six billion, one hundred eleven million, five hundred one", and thus it is an aban number.
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