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561123000901 = 3139971787033
BaseRepresentation
bin10000010101001011000…
…10011000001001000101
31222122100121220212121201
420022211202120021011
533143134442012101
61105435405142501
755353102545221
oct10124542301105
91878317825551
10561123000901
111a6a7533a781
12908bab5aa31
1340bb544cc28
141d230cc1781
15e8e1c61e01
hex82a5898245

561123000901 has 4 divisors (see below), whose sum is σ = 561125101932. Its totient is φ = 561120899872.

The previous prime is 561123000871. The next prime is 561123000929. The reversal of 561123000901 is 109000321165.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 291787950276 + 269335050625 = 540174^2 + 518975^2 .

It is a cyclic number.

It is not a de Polignac number, because 561123000901 - 25 = 561123000869 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 561123000901.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (561123000941) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 579520 + ... + 1207513.

It is an arithmetic number, because the mean of its divisors is an integer number (140281275483).

Almost surely, 2561123000901 is an apocalyptic number.

It is an amenable number.

561123000901 is a deficient number, since it is larger than the sum of its proper divisors (2101031).

561123000901 is a wasteful number, since it uses less digits than its factorization.

561123000901 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2101030.

The product of its (nonzero) digits is 1620, while the sum is 28.

The spelling of 561123000901 in words is "five hundred sixty-one billion, one hundred twenty-three million, nine hundred one", and thus it is an aban number.

Divisors: 1 313997 1787033 561123000901