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56113200421 is a prime number
BaseRepresentation
bin110100010000100110…
…110111110100100101
312100211121212221002021
4310100212313310211
51404404434403141
641440020343141
74024352222335
oct642046676445
9170747787067
1056113200421
1121885491003
12aa60244ab1
1353a3421795
142a045a90c5
1516d63dd6d1
hexd109b7d25

56113200421 has 2 divisors, whose sum is σ = 56113200422. Its totient is φ = 56113200420.

The previous prime is 56113200397. The next prime is 56113200433. The reversal of 56113200421 is 12400231165.

It is a happy number.

56113200421 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 54023704900 + 2089495521 = 232430^2 + 45711^2 .

It is a cyclic number.

It is not a de Polignac number, because 56113200421 - 25 = 56113200389 is a prime.

It is a super-2 number, since 2×561132004212 (a number of 22 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (56113201421) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28056600210 + 28056600211.

It is an arithmetic number, because the mean of its divisors is an integer number (28056600211).

Almost surely, 256113200421 is an apocalyptic number.

It is an amenable number.

56113200421 is a deficient number, since it is larger than the sum of its proper divisors (1).

56113200421 is an equidigital number, since it uses as much as digits as its factorization.

56113200421 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 56113200421 its reverse (12400231165), we get a palindrome (68513431586).

The spelling of 56113200421 in words is "fifty-six billion, one hundred thirteen million, two hundred thousand, four hundred twenty-one".