56113641401 has 2 divisors, whose sum is σ = 56113641402. Its totient is φ = 56113641400.

The previous prime is 56113641391. The next prime is 56113641433. The reversal of 56113641401 is 10414631165.

It is an a-pointer prime, because the next prime (56113641433) can be obtained adding 56113641401 to its sum of digits (32).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 53881551376 + 2232090025 = 232124^2 + 47245^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-56113641401 is a prime.

It is not a weakly prime, because it can be changed into another prime (56113641481) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28056820700 + 28056820701.

It is an arithmetic number, because the mean of its divisors is an integer number (28056820701).

Almost surely, 2^56113641401 is an apocalyptic number.

It is an amenable number.

56113641401 is a deficient number, since it is larger than the sum of its proper divisors (1).

56113641401 is an equidigital number, since it uses as much as digits as its factorization.

56113641401 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8640, while the sum is 32.

The spelling of 56113641401 in words is "fifty-six billion, one hundred thirteen million, six hundred forty-one thousand, four hundred one".