Base | Representation |
---|---|
bin | 11001100001010111011010… |
… | …01101011010001111101111 |
3 | 21100201012202020101020210020 |
4 | 30300223231031122033233 |
5 | 24324000400213430403 |
6 | 315210033504013223 |
7 | 14551453014313434 |
oct | 1460535515321757 |
9 | 240635666336706 |
10 | 56122022405103 |
11 | 16978241605536 |
12 | 63649a7901213 |
13 | 254138cc5a535 |
14 | dc046b18bb8b |
15 | 674ce13d9453 |
hex | 330aed35a3ef |
56122022405103 has 8 divisors (see below), whose sum is σ = 74830925043888. Its totient is φ = 37413900684864.
The previous prime is 56122022405101. The next prime is 56122022405171. The reversal of 56122022405103 is 30150422022165.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 56122022405103 - 21 = 56122022405101 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (56122022405101) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 195061926 + ... + 195349427.
It is an arithmetic number, because the mean of its divisors is an integer number (9353865630486).
Almost surely, 256122022405103 is an apocalyptic number.
56122022405103 is a deficient number, since it is larger than the sum of its proper divisors (18708902638785).
56122022405103 is a wasteful number, since it uses less digits than its factorization.
56122022405103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 390459273.
The product of its (nonzero) digits is 28800, while the sum is 33.
Adding to 56122022405103 its reverse (30150422022165), we get a palindrome (86272444427268).
The spelling of 56122022405103 in words is "fifty-six trillion, one hundred twenty-two billion, twenty-two million, four hundred five thousand, one hundred three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •