Base | Representation |
---|---|
bin | 11001100001101100011100… |
… | …00101010000001100101101 |
3 | 21100202021212222111012210222 |
4 | 30300312032011100030231 |
5 | 24324142010200130130 |
6 | 315215142012541125 |
7 | 14552332532523233 |
oct | 1460661605201455 |
9 | 240667788435728 |
10 | 56133311333165 |
11 | 16982004945250 |
12 | 63670184817a5 |
13 | 254246b9a7221 |
14 | dc0c1c58c953 |
15 | 6752524ebce5 |
hex | 330d8e15032d |
56133311333165 has 16 divisors (see below), whose sum is σ = 73488474792576. Its totient is φ = 40821522408000.
The previous prime is 56133311333027. The next prime is 56133311333173.
56133311333165 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 56133311333165 - 214 = 56133311316781 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 32962097 + ... + 34623206.
It is an arithmetic number, because the mean of its divisors is an integer number (4593029674536).
Almost surely, 256133311333165 is an apocalyptic number.
56133311333165 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
It is an amenable number.
56133311333165 is a deficient number, since it is larger than the sum of its proper divisors (17355163459411).
56133311333165 is a wasteful number, since it uses less digits than its factorization.
56133311333165 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 67600420.
The product of its digits is 656100, while the sum is 44.
It can be divided in two parts, 5613331 and 1333165, that added together give a palindrome (6946496).
The spelling of 56133311333165 in words is "fifty-six trillion, one hundred thirty-three billion, three hundred eleven million, three hundred thirty-three thousand, one hundred sixty-five".
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