Base | Representation |
---|---|
bin | 11001100001111001001100… |
… | …00110000100001101111101 |
3 | 21100202221120001011100200122 |
4 | 30300330212012010031331 |
5 | 24324300020100302430 |
6 | 315222233143504325 |
7 | 14552664263000234 |
oct | 1460744606041575 |
9 | 240687501140618 |
10 | 56140156650365 |
11 | 169849a7949397 |
12 | 6368408a580a5 |
13 | 2542cbcc31988 |
14 | dc12ab761b1b |
15 | 67550345dee5 |
hex | 330f2618437d |
56140156650365 has 4 divisors (see below), whose sum is σ = 67368187980444. Its totient is φ = 44912125320288.
The previous prime is 56140156650287. The next prime is 56140156650379. The reversal of 56140156650365 is 56305665104165.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 38912169913444 + 17227986736921 = 6237962^2 + 4150661^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-56140156650365 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5614015665032 + ... + 5614015665041.
It is an arithmetic number, because the mean of its divisors is an integer number (16842046995111).
Almost surely, 256140156650365 is an apocalyptic number.
It is an amenable number.
56140156650365 is a deficient number, since it is larger than the sum of its proper divisors (11228031330079).
56140156650365 is a wasteful number, since it uses less digits than its factorization.
56140156650365 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11228031330078.
The product of its (nonzero) digits is 9720000, while the sum is 53.
The spelling of 56140156650365 in words is "fifty-six trillion, one hundred forty billion, one hundred fifty-six million, six hundred fifty thousand, three hundred sixty-five".
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