Base | Representation |
---|---|
bin | 11001100010110011100001… |
… | …01100111110101110011100 |
3 | 21100212221101112122200120222 |
4 | 30301121300230332232130 |
5 | 24330303134110332130 |
6 | 315244452444500512 |
7 | 14555153316512216 |
oct | 1461316054765634 |
9 | 240787345580528 |
10 | 56171473136540 |
11 | 1699720821aa23 |
12 | 63724a884a738 |
13 | 2545c40c84978 |
14 | dc29dc97d5b6 |
15 | 676237932ce5 |
hex | 331670b3eb9c |
56171473136540 has 24 divisors (see below), whose sum is σ = 117962709440352. Its totient is φ = 22468090996800.
The previous prime is 56171473136507. The next prime is 56171473136549. The reversal of 56171473136540 is 4563137417165.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (56171473136549) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 30216011 + ... + 32021090.
It is an arithmetic number, because the mean of its divisors is an integer number (4915112893348).
Almost surely, 256171473136540 is an apocalyptic number.
It is an amenable number.
56171473136540 is an abundant number, since it is smaller than the sum of its proper divisors (61791236303812).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
56171473136540 is a wasteful number, since it uses less digits than its factorization.
56171473136540 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 62282237 (or 62282235 counting only the distinct ones).
The product of its (nonzero) digits is 6350400, while the sum is 53.
The spelling of 56171473136540 in words is "fifty-six trillion, one hundred seventy-one billion, four hundred seventy-three million, one hundred thirty-six thousand, five hundred forty".
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