Base | Representation |
---|---|
bin | 11001100100100000101001… |
… | …11100000010111001100111 |
3 | 21101002112121210001102212011 |
4 | 30302100110330002321213 |
5 | 24332233132124432241 |
6 | 315331422343335051 |
7 | 14562326245263334 |
oct | 1462202474027147 |
9 | 241075553042764 |
10 | 56230063124071 |
11 | 16a0a04379a821 |
12 | 638191a451487 |
13 | 254b61a568c45 |
14 | dc579a07598b |
15 | 677a164b4281 |
hex | 332414f02e67 |
56230063124071 has 2 divisors, whose sum is σ = 56230063124072. Its totient is φ = 56230063124070.
The previous prime is 56230063124041. The next prime is 56230063124113. The reversal of 56230063124071 is 17042136003265.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 56230063124071 - 27 = 56230063123943 is a prime.
It is a super-3 number, since 3×562300631240713 (a number of 42 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (56230063124041) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28115031562035 + 28115031562036.
It is an arithmetic number, because the mean of its divisors is an integer number (28115031562036).
Almost surely, 256230063124071 is an apocalyptic number.
56230063124071 is a deficient number, since it is larger than the sum of its proper divisors (1).
56230063124071 is an equidigital number, since it uses as much as digits as its factorization.
56230063124071 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 181440, while the sum is 40.
The spelling of 56230063124071 in words is "fifty-six trillion, two hundred thirty billion, sixty-three million, one hundred twenty-four thousand, seventy-one".
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