Base | Representation |
---|---|
bin | 11001100111110101010010… |
… | …10110100001111000001101 |
3 | 21101111110021201120121200121 |
4 | 30303322221112201320031 |
5 | 24341120431343304430 |
6 | 315500102305424541 |
7 | 14603510231634046 |
oct | 1463725126417015 |
9 | 241443251517617 |
10 | 56344222244365 |
11 | 16a534a5625530 |
12 | 639ba7a03b151 |
13 | 255931162a773 |
14 | dcb10978d8cd |
15 | 67a9987b3a7a |
hex | 333ea95a1e0d |
56344222244365 has 16 divisors (see below), whose sum is σ = 73760641932096. Its totient is φ = 40977097948800.
The previous prime is 56344222244363. The next prime is 56344222244419.
56344222244365 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 56344222244365 - 21 = 56344222244363 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (56344222244363) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2062227 + ... + 10813936.
It is an arithmetic number, because the mean of its divisors is an integer number (4610040120756).
Almost surely, 256344222244365 is an apocalyptic number.
56344222244365 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
It is an amenable number.
56344222244365 is a deficient number, since it is larger than the sum of its proper divisors (17416419687731).
56344222244365 is a wasteful number, since it uses less digits than its factorization.
56344222244365 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12955740.
The product of its digits is 33177600, while the sum is 52.
It can be divided in two parts, 5634422 and 2244365, that added together give a palindrome (7878787).
The spelling of 56344222244365 in words is "fifty-six trillion, three hundred forty-four billion, two hundred twenty-two million, two hundred forty-four thousand, three hundred sixty-five".
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