Base | Representation |
---|---|
bin | 101001000010011100100… |
… | …1100110010001101011101 |
3 | 201222012110211200000211111 |
4 | 1102010321030302031131 |
5 | 1214402213414243344 |
6 | 15555032412422021 |
7 | 1121331460344202 |
oct | 122047114621535 |
9 | 21865424600744 |
10 | 5640251712349 |
11 | 1885021061331 |
12 | 771150a77911 |
13 | 31bb47c95c37 |
14 | 156dbd7dbca9 |
15 | 9bab11e7834 |
hex | 5213933235d |
5640251712349 has 2 divisors, whose sum is σ = 5640251712350. Its totient is φ = 5640251712348.
The previous prime is 5640251712343. The next prime is 5640251712367. The reversal of 5640251712349 is 9432171520465.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2906404413124 + 2733847299225 = 1704818^2 + 1653435^2 .
It is a cyclic number.
It is not a de Polignac number, because 5640251712349 - 227 = 5640117494621 is a prime.
It is a super-3 number, since 3×56402517123493 (a number of 39 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5640251712343) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2820125856174 + 2820125856175.
It is an arithmetic number, because the mean of its divisors is an integer number (2820125856175).
Almost surely, 25640251712349 is an apocalyptic number.
It is an amenable number.
5640251712349 is a deficient number, since it is larger than the sum of its proper divisors (1).
5640251712349 is an equidigital number, since it uses as much as digits as its factorization.
5640251712349 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1814400, while the sum is 49.
The spelling of 5640251712349 in words is "five trillion, six hundred forty billion, two hundred fifty-one million, seven hundred twelve thousand, three hundred forty-nine".
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