Base | Representation |
---|---|
bin | 101001000010011100100… |
… | …1100110010001101101111 |
3 | 201222012110211200000212011 |
4 | 1102010321030302031233 |
5 | 1214402213414243432 |
6 | 15555032412422051 |
7 | 1121331460344226 |
oct | 122047114621557 |
9 | 21865424600764 |
10 | 5640251712367 |
11 | 1885021061348 |
12 | 771150a77927 |
13 | 31bb47c95c4c |
14 | 156dbd7dbcbd |
15 | 9bab11e7847 |
hex | 5213933236f |
5640251712367 has 2 divisors, whose sum is σ = 5640251712368. Its totient is φ = 5640251712366.
The previous prime is 5640251712349. The next prime is 5640251712413. The reversal of 5640251712367 is 7632171520465.
5640251712367 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5640251712367 - 235 = 5605891973999 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 5640251712367.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5640251722367) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2820125856183 + 2820125856184.
It is an arithmetic number, because the mean of its divisors is an integer number (2820125856184).
Almost surely, 25640251712367 is an apocalyptic number.
5640251712367 is a deficient number, since it is larger than the sum of its proper divisors (1).
5640251712367 is an equidigital number, since it uses as much as digits as its factorization.
5640251712367 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2116800, while the sum is 49.
The spelling of 5640251712367 in words is "five trillion, six hundred forty billion, two hundred fifty-one million, seven hundred twelve thousand, three hundred sixty-seven".
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