Base | Representation |
---|---|
bin | 1000000001000100110101010… |
… | …1100101001010000001101001 |
3 | 2201222102112121020122001110021 |
4 | 2000101031111211022001221 |
5 | 1042420221332314401330 |
6 | 5315450521205120441 |
7 | 226553141243121562 |
oct | 20021152545120151 |
9 | 2658375536561407 |
10 | 564132505231465 |
11 | 1538282853320a5 |
12 | 533307aa6b9121 |
13 | 1b2a160bc53ac1 |
14 | 9d442321b1169 |
15 | 45345ab1d067a |
hex | 201135594a069 |
564132505231465 has 16 divisors (see below), whose sum is σ = 708648850067328. Its totient is φ = 430304821854336.
The previous prime is 564132505231453. The next prime is 564132505231469.
564132505231465 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 564132505231465 - 211 = 564132505229417 is a prime.
It is a super-3 number, since 3×5641325052314653 (a number of 45 digits) contains 333 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (564132505231469) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 7836226059 + ... + 7836298048.
It is an arithmetic number, because the mean of its divisors is an integer number (44290553129208).
Almost surely, 2564132505231465 is an apocalyptic number.
It is an amenable number.
564132505231465 is a deficient number, since it is larger than the sum of its proper divisors (144516344835863).
564132505231465 is a wasteful number, since it uses less digits than its factorization.
564132505231465 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 15672524448.
The product of its (nonzero) digits is 12960000, while the sum is 52.
The spelling of 564132505231465 in words is "five hundred sixty-four trillion, one hundred thirty-two billion, five hundred five million, two hundred thirty-one thousand, four hundred sixty-five".
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