Base | Representation |
---|---|
bin | 101001010010110101010… |
… | …1000001011101110011111 |
3 | 202002120022012222200000001 |
4 | 1102211222220023232133 |
5 | 1220441300310413303 |
6 | 20023132251115131 |
7 | 1124015466060502 |
oct | 122455250135637 |
9 | 22076265880001 |
10 | 5675440716703 |
11 | 1898a3936510a |
12 | 777b31742aa7 |
13 | 3222653c40c4 |
14 | 15899b067139 |
15 | 9c97065e31d |
hex | 5296aa0bb9f |
5675440716703 has 2 divisors, whose sum is σ = 5675440716704. Its totient is φ = 5675440716702.
The previous prime is 5675440716601. The next prime is 5675440716763. The reversal of 5675440716703 is 3076170445765.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5675440716703 - 241 = 3476417461151 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5675440716763) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2837720358351 + 2837720358352.
It is an arithmetic number, because the mean of its divisors is an integer number (2837720358352).
Almost surely, 25675440716703 is an apocalyptic number.
5675440716703 is a deficient number, since it is larger than the sum of its proper divisors (1).
5675440716703 is an equidigital number, since it uses as much as digits as its factorization.
5675440716703 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 14817600, while the sum is 55.
The spelling of 5675440716703 in words is "five trillion, six hundred seventy-five billion, four hundred forty million, seven hundred sixteen thousand, seven hundred three".
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