Base | Representation |
---|---|
bin | 110100111001110000… |
… | …001101010001011111 |
3 | 12102121201211110112002 |
4 | 310321300031101133 |
5 | 1412313144412224 |
6 | 42032320232515 |
7 | 4050433616621 |
oct | 647160152137 |
9 | 172551743462 |
10 | 56803513439 |
11 | 220aa114432 |
12 | b01346b73b |
13 | 548344b91a |
14 | 2a6c140c11 |
15 | 1726cea9ae |
hex | d39c0d45f |
56803513439 has 2 divisors, whose sum is σ = 56803513440. Its totient is φ = 56803513438.
The previous prime is 56803513423. The next prime is 56803513451. The reversal of 56803513439 is 93431530865.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 56803513439 - 24 = 56803513423 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 56803513393 and 56803513402.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (56803533439) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28401756719 + 28401756720.
It is an arithmetic number, because the mean of its divisors is an integer number (28401756720).
Almost surely, 256803513439 is an apocalyptic number.
56803513439 is a deficient number, since it is larger than the sum of its proper divisors (1).
56803513439 is an equidigital number, since it uses as much as digits as its factorization.
56803513439 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1166400, while the sum is 47.
The spelling of 56803513439 in words is "fifty-six billion, eight hundred three million, five hundred thirteen thousand, four hundred thirty-nine".
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