Base | Representation |
---|---|
bin | 110100111001110000… |
… | …001101010001101011 |
3 | 12102121201211110112112 |
4 | 310321300031101223 |
5 | 1412313144412301 |
6 | 42032320232535 |
7 | 4050433616636 |
oct | 647160152153 |
9 | 172551743475 |
10 | 56803513451 |
11 | 220aa114443 |
12 | b01346b74b |
13 | 548344b929 |
14 | 2a6c140c1d |
15 | 1726cea9bb |
hex | d39c0d46b |
56803513451 has 2 divisors, whose sum is σ = 56803513452. Its totient is φ = 56803513450.
The previous prime is 56803513439. The next prime is 56803513477. The reversal of 56803513451 is 15431530865.
56803513451 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 56803513451 - 26 = 56803513387 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 56803513399 and 56803513408.
It is not a weakly prime, because it can be changed into another prime (56803513751) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28401756725 + 28401756726.
It is an arithmetic number, because the mean of its divisors is an integer number (28401756726).
Almost surely, 256803513451 is an apocalyptic number.
56803513451 is a deficient number, since it is larger than the sum of its proper divisors (1).
56803513451 is an equidigital number, since it uses as much as digits as its factorization.
56803513451 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 216000, while the sum is 41.
The spelling of 56803513451 in words is "fifty-six billion, eight hundred three million, five hundred thirteen thousand, four hundred fifty-one".
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