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56803513477 is a prime number
BaseRepresentation
bin110100111001110000…
…001101010010000101
312102121201211110120111
4310321300031102011
51412313144412402
642032320233021
74050433620004
oct647160152205
9172551743514
1056803513477
11220aa114467
12b01346b771
13548344b949
142a6c140c3b
151726cea9d7
hexd39c0d485

56803513477 has 2 divisors, whose sum is σ = 56803513478. Its totient is φ = 56803513476.

The previous prime is 56803513451. The next prime is 56803513513. The reversal of 56803513477 is 77431530865.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 51983544001 + 4819969476 = 227999^2 + 69426^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-56803513477 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 56803513477.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (56803513777) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28401756738 + 28401756739.

It is an arithmetic number, because the mean of its divisors is an integer number (28401756739).

Almost surely, 256803513477 is an apocalyptic number.

It is an amenable number.

56803513477 is a deficient number, since it is larger than the sum of its proper divisors (1).

56803513477 is an equidigital number, since it uses as much as digits as its factorization.

56803513477 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2116800, while the sum is 49.

The spelling of 56803513477 in words is "fifty-six billion, eight hundred three million, five hundred thirteen thousand, four hundred seventy-seven".