Base | Representation |
---|---|
bin | 110101000001101111… |
… | …110000110000001111 |
3 | 12102222002011111101112 |
4 | 311001233300300033 |
5 | 1413102012124401 |
6 | 42053510402235 |
7 | 4053652510442 |
oct | 650157606017 |
9 | 172862144345 |
10 | 56937614351 |
11 | 22168887432 |
12 | b05036037b |
13 | 54a5171b87 |
14 | 2a81c8b659 |
15 | 17339893bb |
hex | d41bf0c0f |
56937614351 has 2 divisors, whose sum is σ = 56937614352. Its totient is φ = 56937614350.
The previous prime is 56937614249. The next prime is 56937614353. The reversal of 56937614351 is 15341673965.
56937614351 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 56937614351 - 214 = 56937597967 is a prime.
Together with 56937614353, it forms a pair of twin primes.
It is a Chen prime.
It is a self number, because there is not a number n which added to its sum of digits gives 56937614351.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (56937614353) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28468807175 + 28468807176.
It is an arithmetic number, because the mean of its divisors is an integer number (28468807176).
Almost surely, 256937614351 is an apocalyptic number.
56937614351 is a deficient number, since it is larger than the sum of its proper divisors (1).
56937614351 is an equidigital number, since it uses as much as digits as its factorization.
56937614351 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2041200, while the sum is 50.
The spelling of 56937614351 in words is "fifty-six billion, nine hundred thirty-seven million, six hundred fourteen thousand, three hundred fifty-one".
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