Base | Representation |
---|---|
bin | 110101001100001011… |
… | …000100010001101101 |
3 | 12110102021022212020221 |
4 | 311030023010101231 |
5 | 1413431302404430 |
6 | 42123120011341 |
7 | 4061205421462 |
oct | 651413042155 |
9 | 173367285227 |
10 | 57112544365 |
11 | 222485a6998 |
12 | b09aa60b51 |
13 | 550248c166 |
14 | 2a9b1c5669 |
15 | 1743ee057a |
hex | d4c2c446d |
57112544365 has 4 divisors (see below), whose sum is σ = 68535053244. Its totient is φ = 45690035488.
The previous prime is 57112544311. The next prime is 57112544431. The reversal of 57112544365 is 56344521175.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 31050316521 + 26062227844 = 176211^2 + 161438^2 .
It is a cyclic number.
It is not a de Polignac number, because 57112544365 - 227 = 56978326637 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5711254432 + ... + 5711254441.
It is an arithmetic number, because the mean of its divisors is an integer number (17133763311).
Almost surely, 257112544365 is an apocalyptic number.
It is an amenable number.
57112544365 is a deficient number, since it is larger than the sum of its proper divisors (11422508879).
57112544365 is a wasteful number, since it uses less digits than its factorization.
57112544365 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11422508878.
The product of its digits is 504000, while the sum is 43.
The spelling of 57112544365 in words is "fifty-seven billion, one hundred twelve million, five hundred forty-four thousand, three hundred sixty-five".
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