Base | Representation |
---|---|
bin | 110101001100010101… |
… | …000000101101100111 |
3 | 12110102110020022011122 |
4 | 311030111000231213 |
5 | 1413432434314312 |
6 | 42123251524155 |
7 | 4061236526552 |
oct | 651425005547 |
9 | 173373208148 |
10 | 57115151207 |
11 | 2224a017504 |
12 | b09b8b965b |
13 | 5502b9287a |
14 | 2a9b6a3699 |
15 | 1744357b72 |
hex | d4c540b67 |
57115151207 has 2 divisors, whose sum is σ = 57115151208. Its totient is φ = 57115151206.
The previous prime is 57115151123. The next prime is 57115151231. The reversal of 57115151207 is 70215151175.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 57115151207 - 218 = 57114889063 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (57115151707) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28557575603 + 28557575604.
It is an arithmetic number, because the mean of its divisors is an integer number (28557575604).
Almost surely, 257115151207 is an apocalyptic number.
57115151207 is a deficient number, since it is larger than the sum of its proper divisors (1).
57115151207 is an equidigital number, since it uses as much as digits as its factorization.
57115151207 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12250, while the sum is 35.
The spelling of 57115151207 in words is "fifty-seven billion, one hundred fifteen million, one hundred fifty-one thousand, two hundred seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.076 sec. • engine limits •