Base | Representation |
---|---|
bin | 110101001110001111… |
… | …110100111110111001 |
3 | 12110111200211000022201 |
4 | 311032033310332321 |
5 | 1414014210044443 |
6 | 42130401550201 |
7 | 4062110301511 |
oct | 651617647671 |
9 | 173450730281 |
10 | 57147346873 |
11 | 222662075a1 |
12 | b0aa645361 |
13 | 5509756066 |
14 | 2aa1a84841 |
15 | 17470b734d |
hex | d4e3f4fb9 |
57147346873 has 2 divisors, whose sum is σ = 57147346874. Its totient is φ = 57147346872.
The previous prime is 57147346871. The next prime is 57147346877. The reversal of 57147346873 is 37864374175.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 40431959929 + 16715386944 = 201077^2 + 129288^2 .
It is a cyclic number.
It is not a de Polignac number, because 57147346873 - 21 = 57147346871 is a prime.
Together with 57147346871, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (57147346871) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28573673436 + 28573673437.
It is an arithmetic number, because the mean of its divisors is an integer number (28573673437).
Almost surely, 257147346873 is an apocalyptic number.
It is an amenable number.
57147346873 is a deficient number, since it is larger than the sum of its proper divisors (1).
57147346873 is an equidigital number, since it uses as much as digits as its factorization.
57147346873 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 11854080, while the sum is 55.
The spelling of 57147346873 in words is "fifty-seven billion, one hundred forty-seven million, three hundred forty-six thousand, eight hundred seventy-three".
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