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57481127773 is a prime number
BaseRepresentation
bin110101100010001001…
…000110011101011101
312111100221212211122021
4311202021012131131
51420210132042043
642223444020141
74103302344616
oct654211063535
9174327784567
1057481127773
1122417664083
12b182391651
135560950a54
142ad412cc0d
15176654a3ed
hexd6224675d

57481127773 has 2 divisors, whose sum is σ = 57481127774. Its totient is φ = 57481127772.

The previous prime is 57481127771. The next prime is 57481127789. The reversal of 57481127773 is 37772118475.

57481127773 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 55188346084 + 2292781689 = 234922^2 + 47883^2 .

It is a cyclic number.

It is not a de Polignac number, because 57481127773 - 21 = 57481127771 is a prime.

Together with 57481127771, it forms a pair of twin primes.

It is a self number, because there is not a number n which added to its sum of digits gives 57481127773.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (57481127771) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28740563886 + 28740563887.

It is an arithmetic number, because the mean of its divisors is an integer number (28740563887).

Almost surely, 257481127773 is an apocalyptic number.

It is an amenable number.

57481127773 is a deficient number, since it is larger than the sum of its proper divisors (1).

57481127773 is an equidigital number, since it uses as much as digits as its factorization.

57481127773 is an evil number, because the sum of its binary digits is even.

The product of its digits is 2304960, while the sum is 52.

The spelling of 57481127773 in words is "fifty-seven billion, four hundred eighty-one million, one hundred twenty-seven thousand, seven hundred seventy-three".