Base | Representation |
---|---|
bin | 1010101110010111… |
… | …11101010111001101 |
3 | 112212021011111000101 |
4 | 11113023331113031 |
5 | 43242434020023 |
6 | 2351155531101 |
7 | 262452545503 |
oct | 52713752715 |
9 | 15767144011 |
10 | 5757720013 |
11 | 24950a02a1 |
12 | 11482b9a91 |
13 | 709b2a226 |
14 | 3c8982673 |
15 | 23a72b1ad |
hex | 1572fd5cd |
5757720013 has 2 divisors, whose sum is σ = 5757720014. Its totient is φ = 5757720012.
The previous prime is 5757720011. The next prime is 5757720041. The reversal of 5757720013 is 3100277575.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 4943074249 + 814645764 = 70307^2 + 28542^2 .
It is a cyclic number.
It is not a de Polignac number, because 5757720013 - 21 = 5757720011 is a prime.
Together with 5757720011, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5757720011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2878860006 + 2878860007.
It is an arithmetic number, because the mean of its divisors is an integer number (2878860007).
Almost surely, 25757720013 is an apocalyptic number.
It is an amenable number.
5757720013 is a deficient number, since it is larger than the sum of its proper divisors (1).
5757720013 is an equidigital number, since it uses as much as digits as its factorization.
5757720013 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 51450, while the sum is 37.
The square root of 5757720013 is about 75879.6416240878. The cubic root of 5757720013 is about 1792.3253501738.
Adding to 5757720013 its reverse (3100277575), we get a palindrome (8857997588).
The spelling of 5757720013 in words is "five billion, seven hundred fifty-seven million, seven hundred twenty thousand, thirteen".
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