Base | Representation |
---|---|
bin | 11010011011111010001000… |
… | …11010010111010111011100 |
3 | 21121211111210200000020222102 |
4 | 31031331010122113113130 |
5 | 30104424432202113000 |
6 | 323350101451104232 |
7 | 15150003032604662 |
oct | 1515750432272734 |
9 | 247744720006872 |
10 | 58133530113500 |
11 | 17583323235a26 |
12 | 662a801742078 |
13 | 2658c7866caca |
14 | 104d96c10cc32 |
15 | 6ac2be7e33d5 |
hex | 34df446975dc |
58133530113500 has 24 divisors (see below), whose sum is σ = 126963629768976. Its totient is φ = 23253412045200.
The previous prime is 58133530113499. The next prime is 58133530113569. The reversal of 58133530113500 is 531103533185.
It is a super-2 number, since 2×581335301135002 (a number of 28 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 58133529614 + ... + 58133530613.
It is an arithmetic number, because the mean of its divisors is an integer number (5290151240374).
Almost surely, 258133530113500 is an apocalyptic number.
58133530113500 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
It is an amenable number.
58133530113500 is an abundant number, since it is smaller than the sum of its proper divisors (68830099655476).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
58133530113500 is a wasteful number, since it uses less digits than its factorization.
58133530113500 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 116267060246 (or 116267060234 counting only the distinct ones).
The product of its (nonzero) digits is 81000, while the sum is 38.
Adding to 58133530113500 its reverse (531103533185), we get a palindrome (58664633646685).
The spelling of 58133530113500 in words is "fifty-eight trillion, one hundred thirty-three billion, five hundred thirty million, one hundred thirteen thousand, five hundred".
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