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59140895153 is a prime number
BaseRepresentation
bin110111000101000100…
…100111000110110001
312122122122000202110012
4313011010213012301
51432110032121103
643100254344305
74162365212564
oct670504470661
9178578022405
1059140895153
112309954795a
12b5661bb095
135766781922
142c107404db
1518121032d8
hexdc51271b1

59140895153 has 2 divisors, whose sum is σ = 59140895154. Its totient is φ = 59140895152.

The previous prime is 59140895147. The next prime is 59140895159. The reversal of 59140895153 is 35159804195.

It is a balanced prime because it is at equal distance from previous prime (59140895147) and next prime (59140895159).

It can be written as a sum of positive squares in only one way, i.e., 54956487184 + 4184407969 = 234428^2 + 64687^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-59140895153 is a prime.

It is not a weakly prime, because it can be changed into another prime (59140895159) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 29570447576 + 29570447577.

It is an arithmetic number, because the mean of its divisors is an integer number (29570447577).

Almost surely, 259140895153 is an apocalyptic number.

It is an amenable number.

59140895153 is a deficient number, since it is larger than the sum of its proper divisors (1).

59140895153 is an equidigital number, since it uses as much as digits as its factorization.

59140895153 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 972000, while the sum is 50.

The spelling of 59140895153 in words is "fifty-nine billion, one hundred forty million, eight hundred ninety-five thousand, one hundred fifty-three".