Base | Representation |
---|---|
bin | 110111000101000100… |
… | …101001000110110111 |
3 | 12122122122001011200211 |
4 | 313011010221012313 |
5 | 1432110032401401 |
6 | 43100254450251 |
7 | 4162365245515 |
oct | 670504510667 |
9 | 178578034624 |
10 | 59140903351 |
11 | 23099553032 |
12 | b566203987 |
13 | 576678558a |
14 | 2c107434b5 |
15 | 1812105951 |
hex | dc51291b7 |
59140903351 has 4 divisors (see below), whose sum is σ = 59143316392. Its totient is φ = 59138490312.
The previous prime is 59140903333. The next prime is 59140903357. The reversal of 59140903351 is 15330904195.
59140903351 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 15330904195 = 5 ⋅3066180839.
It is a cyclic number.
It is not a de Polignac number, because 59140903351 - 213 = 59140895159 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (59140903357) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1169376 + ... + 1218901.
It is an arithmetic number, because the mean of its divisors is an integer number (14785829098).
Almost surely, 259140903351 is an apocalyptic number.
59140903351 is a deficient number, since it is larger than the sum of its proper divisors (2413041).
59140903351 is a wasteful number, since it uses less digits than its factorization.
59140903351 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2413040.
The product of its (nonzero) digits is 72900, while the sum is 40.
The spelling of 59140903351 in words is "fifty-nine billion, one hundred forty million, nine hundred three thousand, three hundred fifty-one".
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