Base | Representation |
---|---|
bin | 101011001110011101111… |
… | …0110101010011001010111 |
3 | 210000221121121011122201102 |
4 | 1112130323312222121113 |
5 | 1234314023123034133 |
6 | 20345122035020315 |
7 | 1152135062263352 |
oct | 126347366523127 |
9 | 23027547148642 |
10 | 5940943955543 |
11 | 19905a3a8a143 |
12 | 7bb48a13a69b |
13 | 3412c83493ac |
14 | 167786859299 |
15 | a480e5457e8 |
hex | 5673bdaa657 |
5940943955543 has 2 divisors, whose sum is σ = 5940943955544. Its totient is φ = 5940943955542.
The previous prime is 5940943955539. The next prime is 5940943955603. The reversal of 5940943955543 is 3455593490495.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5940943955543 - 22 = 5940943955539 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 5940943955543.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5940943955533) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2970471977771 + 2970471977772.
It is an arithmetic number, because the mean of its divisors is an integer number (2970471977772).
Almost surely, 25940943955543 is an apocalyptic number.
5940943955543 is a deficient number, since it is larger than the sum of its proper divisors (1).
5940943955543 is an equidigital number, since it uses as much as digits as its factorization.
5940943955543 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 262440000, while the sum is 65.
The spelling of 5940943955543 in words is "five trillion, nine hundred forty billion, nine hundred forty-three million, nine hundred fifty-five thousand, five hundred forty-three".
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