Search a number
-
+
59438132657 is a prime number
BaseRepresentation
bin110111010110110010…
…011110110110110001
312200102100022222122122
4313112302132312301
51433212130221112
643145553244025
74202634535331
oct672662366661
9180370288578
1059438132657
1123231304892
12b629863615
1357b32231c7
142c3bdd50c1
15182d268872
hexdd6c9edb1

59438132657 has 2 divisors, whose sum is σ = 59438132658. Its totient is φ = 59438132656.

The previous prime is 59438132639. The next prime is 59438132659. The reversal of 59438132657 is 75623183495.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 55490398096 + 3947734561 = 235564^2 + 62831^2 .

It is a cyclic number.

It is not a de Polignac number, because 59438132657 - 228 = 59169697201 is a prime.

It is a super-2 number, since 2×594381326572 (a number of 22 digits) contains 22 as substring.

Together with 59438132659, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 59438132599 and 59438132608.

It is not a weakly prime, because it can be changed into another prime (59438132659) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 29719066328 + 29719066329.

It is an arithmetic number, because the mean of its divisors is an integer number (29719066329).

Almost surely, 259438132657 is an apocalyptic number.

It is an amenable number.

59438132657 is a deficient number, since it is larger than the sum of its proper divisors (1).

59438132657 is an equidigital number, since it uses as much as digits as its factorization.

59438132657 is an evil number, because the sum of its binary digits is even.

The product of its digits is 5443200, while the sum is 53.

The spelling of 59438132657 in words is "fifty-nine billion, four hundred thirty-eight million, one hundred thirty-two thousand, six hundred fifty-seven".