6017004331157 has 4 divisors (see below), whose sum is σ = 6017128664460. Its totient is φ = 6016879997856.

The previous prime is 6017004331153. The next prime is 6017004331181. The reversal of 6017004331157 is 7511334007106.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 2710283934436 + 3306720396721 = 1646294^2 + 1818439^2 .

It is a cyclic number.

It is not a de Polignac number, because 6017004331157 - 2² = 6017004331153 is a prime.

It is a super-2 number, since 2×6017004331157² (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 6017004331157.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (6017004331153) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 62094032 + ... + 62190857.

It is an arithmetic number, because the mean of its divisors is an integer number (1504282166115).

Almost surely, 2^{6017004331157} is an apocalyptic number.

It is an amenable number.

6017004331157 is a deficient number, since it is larger than the sum of its proper divisors (124333303).

6017004331157 is a wasteful number, since it uses less digits than its factorization.

6017004331157 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 124333302.

The product of its (nonzero) digits is 52920, while the sum is 38.

The spelling of 6017004331157 in words is "six trillion, seventeen billion, four million, three hundred thirty-one thousand, one hundred fifty-seven".