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60343115981 is a prime number
BaseRepresentation
bin111000001100101110…
…101110000011001101
312202202102012220101112
4320030232232003031
51442040314202411
643415442221405
74234234010561
oct701456560315
9182672186345
1060343115981
1123656130195
12b840954865
1358c8872bb5
142cc628b6a1
15188292bb8b
hexe0cbae0cd

60343115981 has 2 divisors, whose sum is σ = 60343115982. Its totient is φ = 60343115980.

The previous prime is 60343115977. The next prime is 60343115983. The reversal of 60343115981 is 18951134306.

60343115981 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 59870749225 + 472366756 = 244685^2 + 21734^2 .

It is a cyclic number.

It is not a de Polignac number, because 60343115981 - 22 = 60343115977 is a prime.

It is a super-3 number, since 3×603431159813 (a number of 33 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

Together with 60343115983, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (60343115983) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30171557990 + 30171557991.

It is an arithmetic number, because the mean of its divisors is an integer number (30171557991).

Almost surely, 260343115981 is an apocalyptic number.

It is an amenable number.

60343115981 is a deficient number, since it is larger than the sum of its proper divisors (1).

60343115981 is an equidigital number, since it uses as much as digits as its factorization.

60343115981 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 77760, while the sum is 41.

The spelling of 60343115981 in words is "sixty billion, three hundred forty-three million, one hundred fifteen thousand, nine hundred eighty-one".