Base | Representation |
---|---|
bin | 1011001111100111… |
… | …11111000110010100 |
3 | 120120201000111202011 |
4 | 11213303333012110 |
5 | 44330340221330 |
6 | 2435002154004 |
7 | 302410443562 |
oct | 54763770624 |
9 | 16521014664 |
10 | 6036648340 |
11 | 2618592278 |
12 | 12057b2904 |
13 | 75285ab88 |
14 | 413a2ca32 |
15 | 254e7682a |
hex | 167cff194 |
6036648340 has 24 divisors (see below), whose sum is σ = 12698079912. Its totient is φ = 2410636800.
The previous prime is 6036648329. The next prime is 6036648341. The reversal of 6036648340 is 438466306.
It can be written as a sum of positive squares in 4 ways, for example, as 2831729796 + 3204918544 = 53214^2 + 56612^2 .
It is a super-2 number, since 2×60366483402 = 72882246361649511200, which contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 6036648293 and 6036648302.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (6036648341) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 239089 + ... + 263128.
It is an arithmetic number, because the mean of its divisors is an integer number (529086663).
Almost surely, 26036648340 is an apocalyptic number.
It is an amenable number.
6036648340 is an abundant number, since it is smaller than the sum of its proper divisors (6661431572).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
6036648340 is a wasteful number, since it uses less digits than its factorization.
6036648340 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 502827 (or 502825 counting only the distinct ones).
The product of its (nonzero) digits is 248832, while the sum is 40.
The square root of 6036648340 is about 77695.8708040524. The cubic root of 6036648340 is about 1820.8127774974.
The spelling of 6036648340 in words is "six billion, thirty-six million, six hundred forty-eight thousand, three hundred forty".
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