60404973813 has 12 divisors (see below), whose sum is σ = 87438469248. Its totient is φ = 40183748520.

The previous prime is 60404973787. The next prime is 60404973829. The reversal of 60404973813 is 31837940406.

60404973813 is a `hidden beast` number, since 604 + 0 + 4 + 9 + 7 + 38 + 1 + 3 = 666.

It is not a de Polignac number, because 60404973813 - 2⁵ = 60404973781 is a prime.

It is a super-2 number, since 2×60404973813² (a number of 22 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (60404973613) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 7181733 + ... + 7190138.

It is an arithmetic number, because the mean of its divisors is an integer number (7286539104).

Almost surely, 2^60404973813 is an apocalyptic number.

It is an amenable number.

60404973813 is a deficient number, since it is larger than the sum of its proper divisors (27033495435).

60404973813 is a wasteful number, since it uses less digits than its factorization.

60404973813 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 14372344 (or 14372341 counting only the distinct ones).

The product of its (nonzero) digits is 435456, while the sum is 45.

The spelling of 60404973813 in words is "sixty billion, four hundred four million, nine hundred seventy-three thousand, eight hundred thirteen".