61084130477 has 2 divisors, whose sum is σ = 61084130478. Its totient is φ = 61084130476.

The previous prime is 61084130449. The next prime is 61084130479. The reversal of 61084130477 is 77403148016.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 50024242921 + 11059887556 = 223661^2 + 105166^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-61084130477 is a prime.

It is a super-3 number, since 3×61084130477³ (a number of 33 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

Together with 61084130479, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (61084130479) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30542065238 + 30542065239.

It is an arithmetic number, because the mean of its divisors is an integer number (30542065239).

Almost surely, 2^61084130477 is an apocalyptic number.

It is an amenable number.

61084130477 is a deficient number, since it is larger than the sum of its proper divisors (1).

61084130477 is an equidigital number, since it uses as much as digits as its factorization.

61084130477 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 112896, while the sum is 41.

The spelling of 61084130477 in words is "sixty-one billion, eighty-four million, one hundred thirty thousand, four hundred seventy-seven".