Base | Representation |
---|---|
bin | 111000111001110110… |
… | …000000001110000011 |
3 | 12211201011102121020211 |
4 | 320321312000032003 |
5 | 2000113100001011 |
6 | 44022521014551 |
7 | 4262054301112 |
oct | 707166001603 |
9 | 184634377224 |
10 | 61100000131 |
11 | 23a043a2485 |
12 | ba12324457 |
13 | 59b960ac41 |
14 | 2d589d1c79 |
15 | 18c90d8b21 |
hex | e39d80383 |
61100000131 has 2 divisors, whose sum is σ = 61100000132. Its totient is φ = 61100000130.
The previous prime is 61100000083. The next prime is 61100000149. The reversal of 61100000131 is 13100000116.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-61100000131 is a prime.
It is a super-2 number, since 2×611000001312 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (61100000831) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30550000065 + 30550000066.
It is an arithmetic number, because the mean of its divisors is an integer number (30550000066).
Almost surely, 261100000131 is an apocalyptic number.
61100000131 is a deficient number, since it is larger than the sum of its proper divisors (1).
61100000131 is an equidigital number, since it uses as much as digits as its factorization.
61100000131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18, while the sum is 13.
Adding to 61100000131 its reverse (13100000116), we get a palindrome (74200000247).
The spelling of 61100000131 in words is "sixty-one billion, one hundred million, one hundred thirty-one", and thus it is an aban number.
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