Base | Representation |
---|---|
bin | 11011110010101001000101… |
… | …10011010110101101000111 |
3 | 22000101102001222122012201220 |
4 | 31321110202303112231013 |
5 | 31002241300411324341 |
6 | 333551122315251423 |
7 | 15605213542026324 |
oct | 1571244263265507 |
9 | 260342058565656 |
10 | 61113673542471 |
11 | 18522188536a20 |
12 | 6a302a5749b73 |
13 | 2813cc14330a4 |
14 | 1113cbbbb7b4b |
15 | 70ea90b9da66 |
hex | 379522cd6b47 |
61113673542471 has 32 divisors (see below), whose sum is σ = 92758259496960. Its totient is φ = 35427931202400.
The previous prime is 61113673542457. The next prime is 61113673542503. The reversal of 61113673542471 is 17424537631116.
It is not a de Polignac number, because 61113673542471 - 242 = 56715627031367 is a prime.
It is a super-3 number, since 3×611136735424713 (a number of 42 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (61113673542671) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 126769716 + ... + 127250886.
It is an arithmetic number, because the mean of its divisors is an integer number (2898695609280).
Almost surely, 261113673542471 is an apocalyptic number.
61113673542471 is a deficient number, since it is larger than the sum of its proper divisors (31644585954489).
61113673542471 is a wasteful number, since it uses less digits than its factorization.
61113673542471 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 648547.
The product of its digits is 2540160, while the sum is 51.
The spelling of 61113673542471 in words is "sixty-one trillion, one hundred thirteen billion, six hundred seventy-three million, five hundred forty-two thousand, four hundred seventy-one".
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