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61299175492871 is a prime number
BaseRepresentation
bin11011111000000010100111…
…00101001000110100000111
322001001010212221021200001022
431330001103211020310013
531013311202411232441
6334212241422021355
715624501466423211
oct1574012345106407
9261033787250038
1061299175492871
111859391a554948
126a60235a1785b
132828644bc1c94
14111cc785b75b1
157147eb40e84b
hex37c053948d07

61299175492871 has 2 divisors, whose sum is σ = 61299175492872. Its totient is φ = 61299175492870.

The previous prime is 61299175492853. The next prime is 61299175492873. The reversal of 61299175492871 is 17829457199216.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-61299175492871 is a prime.

It is a super-2 number, since 2×612991754928712 (a number of 28 digits) contains 22 as substring.

It is a Sophie Germain prime.

Together with 61299175492873, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 61299175492795 and 61299175492804.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (61299175492873) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30649587746435 + 30649587746436.

It is an arithmetic number, because the mean of its divisors is an integer number (30649587746436).

Almost surely, 261299175492871 is an apocalyptic number.

61299175492871 is a deficient number, since it is larger than the sum of its proper divisors (1).

61299175492871 is an equidigital number, since it uses as much as digits as its factorization.

61299175492871 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 137168640, while the sum is 71.

The spelling of 61299175492871 in words is "sixty-one trillion, two hundred ninety-nine billion, one hundred seventy-five million, four hundred ninety-two thousand, eight hundred seventy-one".