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6134120054401 = 9916189828511
BaseRepresentation
bin101100101000011011000…
…0010111111111010000001
3210201102020101002020122111
41121100312002333322001
51301000134213220101
621013550441135321
71202114133111013
oct131206602777201
923642211066574
106134120054401
111a55513944419
12830a0048a541
133565a299b931
14172c705401b3
15a9868888251
hex594360bfe81

6134120054401 has 4 divisors (see below), whose sum is σ = 6140309883904. Its totient is φ = 6127930224900.

The previous prime is 6134120054399. The next prime is 6134120054431. The reversal of 6134120054401 is 1044500214316.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 6134120054401 - 21 = 6134120054399 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (6134120054431) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3094913265 + ... + 3094915246.

It is an arithmetic number, because the mean of its divisors is an integer number (1535077470976).

Almost surely, 26134120054401 is an apocalyptic number.

It is an amenable number.

6134120054401 is a deficient number, since it is larger than the sum of its proper divisors (6189829503).

6134120054401 is an equidigital number, since it uses as much as digits as its factorization.

6134120054401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6189829502.

The product of its (nonzero) digits is 11520, while the sum is 31.

Adding to 6134120054401 its reverse (1044500214316), we get a palindrome (7178620268717).

The spelling of 6134120054401 in words is "six trillion, one hundred thirty-four billion, one hundred twenty million, fifty-four thousand, four hundred one".

Divisors: 1 991 6189828511 6134120054401