Base | Representation |
---|---|
bin | 11011111110010001111001… |
… | …10100110000010000001111 |
3 | 22001210122012111211100211012 |
4 | 31333020330310300100033 |
5 | 31030314213232403112 |
6 | 334454533041515435 |
7 | 15646130626336412 |
oct | 1577107464602017 |
9 | 261718174740735 |
10 | 61513542075407 |
11 | 18666823935154 |
12 | 6a958a0942b7b |
13 | 2842918760c66 |
14 | 11293b2717b79 |
15 | 71a195c79022 |
hex | 37f23cd3040f |
61513542075407 has 2 divisors, whose sum is σ = 61513542075408. Its totient is φ = 61513542075406.
The previous prime is 61513542075397. The next prime is 61513542075409. The reversal of 61513542075407 is 70457024531516.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 61513542075407 - 238 = 61238664168463 is a prime.
Together with 61513542075409, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (61513542075409) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30756771037703 + 30756771037704.
It is an arithmetic number, because the mean of its divisors is an integer number (30756771037704).
Almost surely, 261513542075407 is an apocalyptic number.
61513542075407 is a deficient number, since it is larger than the sum of its proper divisors (1).
61513542075407 is an equidigital number, since it uses as much as digits as its factorization.
61513542075407 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3528000, while the sum is 50.
The spelling of 61513542075407 in words is "sixty-one trillion, five hundred thirteen billion, five hundred forty-two million, seventy-five thousand, four hundred seven".
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