61588947774833 has 2 divisors, whose sum is σ = 61588947774834. Its totient is φ = 61588947774832.

The previous prime is 61588947774803. The next prime is 61588947774863. The reversal of 61588947774833 is 33847774988516.

61588947774833 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a balanced prime because it is at equal distance from previous prime (61588947774803) and next prime (61588947774863).

It can be written as a sum of positive squares in only one way, i.e., 60297197326129 + 1291750448704 = 7765127^2 + 1136552^2 .

It is a cyclic number.

It is not a de Polignac number, because 61588947774833 - 2¹⁴ = 61588947758449 is a prime.

It is a super-2 number, since 2×61588947774833² (a number of 28 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (61588947774803) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30794473887416 + 30794473887417.

It is an arithmetic number, because the mean of its divisors is an integer number (30794473887417).

Almost surely, 2^{61588947774833} is an apocalyptic number.

It is an amenable number.

61588947774833 is a deficient number, since it is larger than the sum of its proper divisors (1).

61588947774833 is an equidigital number, since it uses as much as digits as its factorization.

61588947774833 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 6827950080, while the sum is 80.

The spelling of 61588947774833 in words is "sixty-one trillion, five hundred eighty-eight billion, nine hundred forty-seven million, seven hundred seventy-four thousand, eight hundred thirty-three".