Base | Representation |
---|---|
bin | 11100000010000101101001… |
… | …00100010101000000011111 |
3 | 22002021010222020012110020011 |
4 | 32001002310210111000133 |
5 | 31034440212403214203 |
6 | 335035014010304051 |
7 | 15661442461656103 |
oct | 1601026444250037 |
9 | 262233866173204 |
10 | 61644400054303 |
11 | 18707274845550 |
12 | 6ab7120a28027 |
13 | 28520713086c1 |
14 | 1131867b21903 |
15 | 71d7a40b876d |
hex | 3810b491501f |
61644400054303 has 8 divisors (see below), whose sum is σ = 67732238125440. Its totient is φ = 55637195600280.
The previous prime is 61644400054283. The next prime is 61644400054333. The reversal of 61644400054303 is 30345000444616.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-61644400054303 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (61644400054333) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 20158402675 + ... + 20158405732.
It is an arithmetic number, because the mean of its divisors is an integer number (8466529765680).
Almost surely, 261644400054303 is an apocalyptic number.
61644400054303 is a deficient number, since it is larger than the sum of its proper divisors (6087838071137).
61644400054303 is a wasteful number, since it uses less digits than its factorization.
61644400054303 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 40316808557.
The product of its (nonzero) digits is 414720, while the sum is 40.
Adding to 61644400054303 its reverse (30345000444616), we get a palindrome (91989400498919).
The spelling of 61644400054303 in words is "sixty-one trillion, six hundred forty-four billion, four hundred million, fifty-four thousand, three hundred three".
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