Base | Representation |
---|---|
bin | 1110110010011… |
… | …0000111100001 |
3 | 11022201001100022 |
4 | 3230212013201 |
5 | 111334201423 |
6 | 10053203225 |
7 | 1352115326 |
oct | 354460741 |
9 | 138631308 |
10 | 62022113 |
11 | 3201214a |
12 | 18930515 |
13 | cb0749a |
14 | 8346b4d |
15 | 56a1dc8 |
hex | 3b261e1 |
62022113 has 2 divisors, whose sum is σ = 62022114. Its totient is φ = 62022112.
The previous prime is 62022109. The next prime is 62022127. The reversal of 62022113 is 31122026.
62022113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 52243984 + 9778129 = 7228^2 + 3127^2 .
It is a cyclic number.
It is not a de Polignac number, because 62022113 - 22 = 62022109 is a prime.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 62022091 and 62022100.
It is not a weakly prime, because it can be changed into another prime (62022133) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 31011056 + 31011057.
It is an arithmetic number, because the mean of its divisors is an integer number (31011057).
Almost surely, 262022113 is an apocalyptic number.
It is an amenable number.
62022113 is a deficient number, since it is larger than the sum of its proper divisors (1).
62022113 is an equidigital number, since it uses as much as digits as its factorization.
62022113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 144, while the sum is 17.
The square root of 62022113 is about 7875.4119257344. The cubic root of 62022113 is about 395.8362095993.
Adding to 62022113 its reverse (31122026), we get a palindrome (93144139).
The spelling of 62022113 in words is "sixty-two million, twenty-two thousand, one hundred thirteen".
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