643251211140 has 48 divisors (see below), whose sum is σ = 1803643853760. Its totient is φ = 171291707520.

The previous prime is 643251211091. The next prime is 643251211177. The reversal of 643251211140 is 41112152346.

It is a Harshad number since it is a multiple of its sum of digits (30).

It is a junction number, because it is equal to n+sod(n) for n = 643251211098 and 643251211107.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 7518006 + ... + 7603085.

It is an arithmetic number, because the mean of its divisors is an integer number (37575913620).

Almost surely, 2^643251211140 is an apocalyptic number.

643251211140 is a gapful number since it is divisible by the number (60) formed by its first and last digit.

It is an amenable number.

643251211140 is an abundant number, since it is smaller than the sum of its proper divisors (1160392642620).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

643251211140 is a wasteful number, since it uses less digits than its factorization.

643251211140 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 15121812 (or 15121810 counting only the distinct ones).

The product of its (nonzero) digits is 5760, while the sum is 30.

Adding to 643251211140 its reverse (41112152346), we get a palindrome (684363363486).

The spelling of 643251211140 in words is "six hundred forty-three billion, two hundred fifty-one million, two hundred eleven thousand, one hundred forty".