Base | Representation |
---|---|
bin | 111011111010101000… |
… | …000010010011001001 |
3 | 20011001120102011021021 |
4 | 323322220002103021 |
5 | 2023224042410241 |
6 | 45315500112441 |
7 | 4435156610215 |
oct | 737250022311 |
9 | 204046364237 |
10 | 64334341321 |
11 | 25314070928 |
12 | 10575535721 |
13 | 60b37116b3 |
14 | 3184399945 |
15 | 1a1801c0d1 |
hex | efaa024c9 |
64334341321 has 2 divisors, whose sum is σ = 64334341322. Its totient is φ = 64334341320.
The previous prime is 64334341319. The next prime is 64334341361. The reversal of 64334341321 is 12314343346.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 35707393296 + 28626948025 = 188964^2 + 169195^2 .
It is a cyclic number.
It is not a de Polignac number, because 64334341321 - 21 = 64334341319 is a prime.
Together with 64334341319, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (64334341361) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32167170660 + 32167170661.
It is an arithmetic number, because the mean of its divisors is an integer number (32167170661).
Almost surely, 264334341321 is an apocalyptic number.
It is an amenable number.
64334341321 is a deficient number, since it is larger than the sum of its proper divisors (1).
64334341321 is an equidigital number, since it uses as much as digits as its factorization.
64334341321 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 62208, while the sum is 34.
Adding to 64334341321 its reverse (12314343346), we get a palindrome (76648684667).
The spelling of 64334341321 in words is "sixty-four billion, three hundred thirty-four million, three hundred forty-one thousand, three hundred twenty-one".
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