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6442542034457 is a prime number
BaseRepresentation
bin101110111000000010101…
…1011011110111000011001
3211210220022211110012002212
41131300011123132320121
51321023311230100312
621411355110404505
71233313124512154
oct135600533367031
924726284405085
106442542034457
1120642a3026a11
12880736360735
133796b55a9699
14183b6bdd2c9b
15b28ba5e8822
hex5dc056dee19

6442542034457 has 2 divisors, whose sum is σ = 6442542034458. Its totient is φ = 6442542034456.

The previous prime is 6442542034421. The next prime is 6442542034459. The reversal of 6442542034457 is 7544302452446.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6369309015001 + 73233019456 = 2523749^2 + 270616^2 .

It is a cyclic number.

It is not a de Polignac number, because 6442542034457 - 212 = 6442542030361 is a prime.

Together with 6442542034459, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (6442542034459) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3221271017228 + 3221271017229.

It is an arithmetic number, because the mean of its divisors is an integer number (3221271017229).

Almost surely, 26442542034457 is an apocalyptic number.

It is an amenable number.

6442542034457 is a deficient number, since it is larger than the sum of its proper divisors (1).

6442542034457 is an equidigital number, since it uses as much as digits as its factorization.

6442542034457 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12902400, while the sum is 50.

The spelling of 6442542034457 in words is "six trillion, four hundred forty-two billion, five hundred forty-two million, thirty-four thousand, four hundred fifty-seven".