Base | Representation |
---|---|
bin | 101110111011100101000… |
… | …1010001011000101000110 |
3 | 211211121221011210122222001 |
4 | 1131313022022023011012 |
5 | 1321134340204411000 |
6 | 21415052521255514 |
7 | 1234002264530341 |
oct | 135671212130506 |
9 | 24747834718861 |
10 | 6450137575750 |
11 | 2067540563570 |
12 | 8820b603459a |
13 | 37a3260a990b |
14 | 18428ca95458 |
15 | b2bb234e46a |
hex | 5ddca28b146 |
6450137575750 has 32 divisors (see below), whose sum is σ = 13172353687584. Its totient is φ = 2345504572000.
The previous prime is 6450137575691. The next prime is 6450137575811. The reversal of 6450137575750 is 575757310546.
It is a super-2 number, since 2×64501375757502 (a number of 26 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (55).
It is a junction number, because it is equal to n+sod(n) for n = 6450137575691 and 6450137575700.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1172749537 + ... + 1172755036.
It is an arithmetic number, because the mean of its divisors is an integer number (411636052737).
Almost surely, 26450137575750 is an apocalyptic number.
6450137575750 is an abundant number, since it is smaller than the sum of its proper divisors (6722216111834).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
6450137575750 is a wasteful number, since it uses less digits than its factorization.
6450137575750 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2345504601 (or 2345504591 counting only the distinct ones).
The product of its (nonzero) digits is 15435000, while the sum is 55.
The spelling of 6450137575750 in words is "six trillion, four hundred fifty billion, one hundred thirty-seven million, five hundred seventy-five thousand, seven hundred fifty".
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