Base | Representation |
---|---|
bin | 10010110010000010101… |
… | …10010001010000101111 |
3 | 2021200201221210102200202 |
4 | 21121001112101100233 |
5 | 41033124402420221 |
6 | 1212244334544115 |
7 | 64424106554114 |
oct | 11310126212057 |
9 | 2250657712622 |
10 | 645341451311 |
11 | 229762475007 |
12 | a50a366803b |
13 | 48b1752073b |
14 | 2333ddd690b |
15 | 11bc0756d0b |
hex | 964159142f |
645341451311 has 4 divisors (see below), whose sum is σ = 645811475592. Its totient is φ = 644871427032.
The previous prime is 645341451283. The next prime is 645341451361. The reversal of 645341451311 is 113154143546.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 645341451311 - 218 = 645341189167 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (645341451361) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 235010081 + ... + 235012826.
It is an arithmetic number, because the mean of its divisors is an integer number (161452868898).
Almost surely, 2645341451311 is an apocalyptic number.
645341451311 is a deficient number, since it is larger than the sum of its proper divisors (470024281).
645341451311 is a wasteful number, since it uses less digits than its factorization.
645341451311 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 470024280.
The product of its digits is 86400, while the sum is 38.
Adding to 645341451311 its reverse (113154143546), we get a palindrome (758495594857).
The spelling of 645341451311 in words is "six hundred forty-five billion, three hundred forty-one million, four hundred fifty-one thousand, three hundred eleven".
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