Base | Representation |
---|---|
bin | 11101100100011011001011… |
… | …00001011101011100111110 |
3 | 22112020011021112011120111012 |
4 | 32302031211201131130332 |
5 | 32010320020032224400 |
6 | 350143130213355222 |
7 | 16460525560353560 |
oct | 1662154541353476 |
9 | 275204245146435 |
10 | 65023213164350 |
11 | 1979a20a752611 |
12 | 7361b26638b12 |
13 | 2a3887cc17b5c |
14 | 120b1d7019330 |
15 | 77b60a18dd35 |
hex | 3b236585d73e |
65023213164350 has 96 divisors (see below), whose sum is σ = 139979599303680. Its totient is φ = 22010028543360.
The previous prime is 65023213164341. The next prime is 65023213164373. The reversal of 65023213164350 is 5346131232056.
It is a super-2 number, since 2×650232131643502 (a number of 28 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 65023213164298 and 65023213164307.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 473216357 + ... + 473353743.
It is an arithmetic number, because the mean of its divisors is an integer number (1458120826080).
Almost surely, 265023213164350 is an apocalyptic number.
65023213164350 is an abundant number, since it is smaller than the sum of its proper divisors (74956386139330).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
65023213164350 is a wasteful number, since it uses less digits than its factorization.
65023213164350 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 154602 (or 154597 counting only the distinct ones).
The product of its (nonzero) digits is 388800, while the sum is 41.
The spelling of 65023213164350 in words is "sixty-five trillion, twenty-three billion, two hundred thirteen million, one hundred sixty-four thousand, three hundred fifty".
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